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Exam study plan

SSC CGL Preparation: Concepts and Practice

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Build your SSC CGL foundations with English and Hindi lessons, worked examples and explained practice across Quantitative Aptitude, General Intelligence and Reasoning, English Comprehension and General Awareness. Study arithmetic, algebra, geometry and trigonometry; practise analogy, classification, series, directions, ranking and clocks; strengthen grammar and constitutional basics. Use the linked topic tests to check understanding and review mistakes. Coverage is expanding subject by subject and does not yet represent the complete SSC CGL syllabus. See the module list and mock-test section for currently available material.

Lessons

Subject → Module → Lesson

English ComprehensionGeneral AwarenessGeneral Intelligence and ReasoningQuantitative Aptitude
Course outline 100
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Lessons 1–50 · Page 1 of 2
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8 lessons
  1. 1
    Natural Numbers, Integers, Rational and Irrational Numbers
  2. 2
    Place Value, Face Value and Number Comparison
  3. 3
    Prime, Composite and Co-prime Numbers
  4. 4
    Factors and Multiples
  5. 5
    Divisibility Tests and Missing Digits
  6. 6
    Remainders in Elementary Number Problems
  7. 7
    Unit Digits and Cyclic Patterns
  8. 8
    Counting Factors of a Number1 practice test

4 lessons
  1. 9
    Operations with Signed Integers
  2. 10
    BODMAS and Nested Brackets
  3. 11
    Simplifying Mixed Numerical Expressions
  4. 12
    Estimation and Checking Numerical Answers1 practice test

3 lessons
  1. 13
    Decimal notation and ordering
  2. 14
    Addition, subtraction, multiplication and division of decimals
  3. 15
    Terminating and recurring decimals

4 lessons
  1. 16
    Proper, improper, mixed and equivalent fractions
  2. 17
    Ordering and comparing fractions
  3. 18
    Arithmetic with fractions
  4. 19
    Converting fractions and decimals1 practice test

5 lessons
  1. 20
    Writing, simplifying and comparing ratios
  2. 21
    Proportion and continued proportion
  3. 22
    Direct and inverse proportion
  4. 23
    Dividing quantities in a ratio
  5. 24
    Compound ratios and changing ratios

7 lessons
  1. 25
    Meaning of percentage and fraction–decimal–percentage conversion
  2. 26
    Finding a percentage of a quantity
  3. 27
    Expressing one quantity as a percentage of another
  4. 28
    Percentage increase and decrease
  5. 29
    Successive percentage changes
  6. 30
    Finding the original quantity from a percentage change
  7. 31
    Population, income, expenditure and price applications

3 lessons
  1. 32
    Arithmetic Average of a Group
  2. 33
    Combined and Weighted Averages
  3. 34
    Average Changes After Addition, Removal or Replacement1 practice test

5 lessons
  1. 35
    Cost price, selling price, profit and loss
  2. 36
    Profit and loss percentages and reverse calculations
  3. 37
    Marked price, discount and markup
  4. 38
    Successive discounts
  5. 39
    Combined profit, loss and discount situations

3 lessons
  1. 40
    Principal, rate, time, simple interest and amount
  2. 41
    Finding an unknown principal, rate or time
  3. 42
    Comparing simple-interest arrangements

4 lessons
  1. 43
    Compound interest and successive accumulation
  2. 44
    Annual and subannual compounding
  3. 45
    Comparing simple and compound interest
  4. 46
    Growth and depreciation through repeated percentage changes

2 lessons
  1. 47
    Capital, time and profit-sharing ratios
  2. 48
    Partners joining, leaving or changing investment

2 lessons
  1. 49
    Concentration and weighted mixture averages
  2. 50
    Alligation for two-component mixtures

50 lessons across 12 modules

Lesson 24 of 100 | Quantitative Aptitude / Ratio and Proportion / अनुपात और समानुपात

Compound ratios and changing ratios

Learning outcome

Form compound ratios, connect shared quantities, and solve changing-ratio problems by tracking changes precisely.

Understanding compound and changing ratios

The compound ratio of a:b and c:d is (a × c):(b × d). This follows from multiplying the fractions a/b and c/d. Multiply corresponding terms, not crosswise; cross-products serve comparison or proportion testing.

If A:B and B:C are known, multiplying A/B by B/C cancels the shared B and gives A/C. This gives the endpoint ratio, not the full three-term ratio. For A:B:C, scale until the B terms match.

Write initial amounts as au and bu, where u > 0 is their common scale and au means a × u. Apply additions or removals to the specified quantities before forming the new ratio. Match units first.

Equal positive scaling preserves a ratio. Equal additions generally change it because relative increases differ; equal initial amounts are an exception. A transfer subtracts from one quantity and adds to the other, preserving the total. Remaining quantities must stay positive.

Worked example 1

Positive lengths satisfy A:B = 2:3 and B:C = 4:5. Find A:C and A:B:C.

Compounding gives A:C = (2 × 4):(3 × 5) = 8:15. For A:B:C, multiply 2:3 by 4 to get 8:12, and 4:5 by 3 to get 12:15. Matching B now gives A:B:C = 8:12:15.

Worked example 2

Two containers hold water in ratio 3:5. Add 8 L to the first only; the second stays unchanged. The new ratio is 5:7. Find the initial amounts.

Let initial amounts be 3u L and 5u L. Then (3u + 8)/(5u) = 5/7. Cross-multiplication gives 21u + 56 = 25u, so 56 = 4u and u = 14. Initially there were 42 L and 70 L. After addition, 50:70 simplifies to 5:7.

Worked example 3

Two boxes have beads in ratio 7:5. Transfer 10 beads from the first to the second; nothing else changes. The new ratio is 4:5. Find the initial counts.

Initially, take 7u and 5u. Then (7u − 10)/(5u + 10) = 4/5. Thus 35u − 50 = 20u + 40, giving 15u = 90 and u = 6. Initially there were 42 and 30 beads. Afterwards there are 32 and 40, giving 4:5. Both totals are 72.

Common mistakes

Identify what a compound ratio represents. Equal additions are not equal scaling. Transfers change both quantities; check that remaining amounts are positive.

Practice questions

  1. Find the compound ratio of 3:8 and 4:9.
  2. For positive quantities, P:Q = 3:4 and Q:R = 6:7. Find P:Q:R and P:R.
  3. Two containers hold water in ratio 2:3. Adding 6 L to each changes it to 3:4. Find the initial amounts.
  4. Two containers hold water in ratio 5:8. Remove 9 L from only the second; the first stays unchanged. The new ratio is 5:6. Find initial amounts.

Worked answers

  1. Multiply corresponding terms: (3 × 4):(8 × 9) = 12:72 = 1:6.
  2. Scale the ratios to 9:12 and 12:14. Hence P:Q:R = 9:12:14 and P:R = 9:14.
  3. Write (2u + 6)/(3u + 6) = 3/4. Then 8u + 24 = 9u + 18, so u = 6. Initially: 12 L and 18 L. Afterwards: 18 L and 24 L, giving 3:4.
  4. Write (5u)/(8u − 9) = 5/6. Then 30u = 40u − 45, so u = 4.5. Initially: 22.5 L and 36 L. Afterwards: 22.5 L and 27 L, both positive, giving 5:6.
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