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Exam study plan

SSC CGL Preparation: Concepts and Practice

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Build your SSC CGL foundations with English and Hindi lessons, worked examples and explained practice across Quantitative Aptitude, General Intelligence and Reasoning, English Comprehension and General Awareness. Study arithmetic, algebra, geometry and trigonometry; practise analogy, classification, series, directions, ranking and clocks; strengthen grammar and constitutional basics. Use the linked topic tests to check understanding and review mistakes. Coverage is expanding subject by subject and does not yet represent the complete SSC CGL syllabus. See the module list and mock-test section for currently available material.

Lessons

Subject → Module → Lesson

English ComprehensionGeneral AwarenessGeneral Intelligence and ReasoningQuantitative Aptitude
Course outline 100
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Lessons 1–50 · Page 1 of 2
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8 lessons
  1. 1
    Natural Numbers, Integers, Rational and Irrational Numbers
  2. 2
    Place Value, Face Value and Number Comparison
  3. 3
    Prime, Composite and Co-prime Numbers
  4. 4
    Factors and Multiples
  5. 5
    Divisibility Tests and Missing Digits
  6. 6
    Remainders in Elementary Number Problems
  7. 7
    Unit Digits and Cyclic Patterns
  8. 8
    Counting Factors of a Number1 practice test

4 lessons
  1. 9
    Operations with Signed Integers
  2. 10
    BODMAS and Nested Brackets
  3. 11
    Simplifying Mixed Numerical Expressions
  4. 12
    Estimation and Checking Numerical Answers1 practice test

3 lessons
  1. 13
    Decimal notation and ordering
  2. 14
    Addition, subtraction, multiplication and division of decimals
  3. 15
    Terminating and recurring decimals

4 lessons
  1. 16
    Proper, improper, mixed and equivalent fractions
  2. 17
    Ordering and comparing fractions
  3. 18
    Arithmetic with fractions
  4. 19
    Converting fractions and decimals1 practice test

5 lessons
  1. 20
    Writing, simplifying and comparing ratios
  2. 21
    Proportion and continued proportion
  3. 22
    Direct and inverse proportion
  4. 23
    Dividing quantities in a ratio
  5. 24
    Compound ratios and changing ratios

7 lessons
  1. 25
    Meaning of percentage and fraction–decimal–percentage conversion
  2. 26
    Finding a percentage of a quantity
  3. 27
    Expressing one quantity as a percentage of another
  4. 28
    Percentage increase and decrease
  5. 29
    Successive percentage changes
  6. 30
    Finding the original quantity from a percentage change
  7. 31
    Population, income, expenditure and price applications

3 lessons
  1. 32
    Arithmetic Average of a Group
  2. 33
    Combined and Weighted Averages
  3. 34
    Average Changes After Addition, Removal or Replacement1 practice test

5 lessons
  1. 35
    Cost price, selling price, profit and loss
  2. 36
    Profit and loss percentages and reverse calculations
  3. 37
    Marked price, discount and markup
  4. 38
    Successive discounts
  5. 39
    Combined profit, loss and discount situations

3 lessons
  1. 40
    Principal, rate, time, simple interest and amount
  2. 41
    Finding an unknown principal, rate or time
  3. 42
    Comparing simple-interest arrangements

4 lessons
  1. 43
    Compound interest and successive accumulation
  2. 44
    Annual and subannual compounding
  3. 45
    Comparing simple and compound interest
  4. 46
    Growth and depreciation through repeated percentage changes

2 lessons
  1. 47
    Capital, time and profit-sharing ratios
  2. 48
    Partners joining, leaving or changing investment

2 lessons
  1. 49
    Concentration and weighted mixture averages
  2. 50
    Alligation for two-component mixtures

50 lessons across 12 modules

Lesson 21 of 100 | Quantitative Aptitude / Ratio and Proportion / अनुपात और समानुपात

Proportion and continued proportion

Learning outcome

Recognise a proportion, find a missing positive term, and explain how continued proportion connects three ordered quantities through the square of the middle term.

Understanding proportion

A proportion states that two ratios are equal. For positive a, b, c and d, writing a:b = c:d means a/b = c/d. Individual quantities may differ; their relative sizes must match.

Multiplying both fractions by b × d gives a × d = b × c. This is the cross-product test. The outside terms a and d are called extremes, while b and c are called means. The product of the extremes equals the product of the means.

This equation does not permit multiplying whichever numbers look convenient. Keep each term in its original position. Write the equality, then isolate the unknown by dividing by its positive coefficient. Substitute the answer into the original ratios to check it.

For measurements of the same kind, match units before testing equality. A numerical cross-product cannot repair a ratio formed using inconsistent units.

Understanding continued proportion

Three positive numbers a, b and c are in continued proportion, in that order, when a:b = b:c. The same middle number appears in both ratios. Cross-multiplication therefore gives b × b = a × c, or b² = a × c.

To find b, seek the positive number whose square equals a × c. This is the geometric mean of the endpoints, not their ordinary arithmetic average. Equivalently, b/a = c/b: moving between successive terms uses the same multiplication factor, not necessarily the same addition.

Worked example 1

Do 1.2 m:80 cm and 9:6 form a proportion?

Convert 1.2 m to 120 cm. Now 120:80 simplifies to 3:2, and 9:6 also simplifies to 3:2. Therefore the ratios form a proportion. Their relative comparisons match despite different original terms.

Worked example 2

Find positive x in 8:14 = x:35.

Cross-multiplication gives 8 × 35 = 14 × x, so 280 = 14 × x. Divide by 14: x = 20. Checking, 8:14 and 20:35 both simplify to 4:7.

Worked example 3

Find positive b when 4, b and 25 are in continued proportion.

Here b² = 4 × 25 = 100, so b = 10. Check: 4:10 and 10:25 both simplify to 2:5. Each successive term is multiplied by 2.5, confirming the relationship.

Common mistakes

Do not treat any three numbers as a continued proportion. Order matters, and the middle term must satisfy the squared relationship. Do not use the arithmetic average automatically or forget to convert units.

Practice questions

  1. Do 18:24 and 27:36 form a proportion? Justify.
  2. Find positive x if 7:12 = 21:x.
  3. Find positive b if 9:b = b:49.
  4. The numbers 6, 15 and positive c are in continued proportion, in that order. Find c.

Worked answers

  1. Yes. Dividing 18:24 by 6 gives 3:4; dividing 27:36 by 9 also gives 3:4.
  2. Cross-multiply: 7 × x = 12 × 21 = 252. Thus x = 36, and 21:36 reduces to 7:12.
  3. The repeated middle term gives b² = 9 × 49 = 441. Therefore b = 21; both ratios reduce to 3:7.
  4. Since 15² = 6 × c, c = 225/6 = 37.5. Checking, 6/15 = 0.4 and 15/37.5 = 0.4 exactly.
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