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Exam study plan

SSC CGL Preparation: Concepts and Practice

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Build your SSC CGL foundations with English and Hindi lessons, worked examples and explained practice across Quantitative Aptitude, General Intelligence and Reasoning, English Comprehension and General Awareness. Study arithmetic, algebra, geometry and trigonometry; practise analogy, classification, series, directions, ranking and clocks; strengthen grammar and constitutional basics. Use the linked topic tests to check understanding and review mistakes. Coverage is expanding subject by subject and does not yet represent the complete SSC CGL syllabus. See the module list and mock-test section for currently available material.

Lessons

Subject → Module → Lesson

English ComprehensionGeneral AwarenessGeneral Intelligence and ReasoningQuantitative Aptitude
Course outline 100
70 / 100
Lessons 51–100 · Page 2 of 2
Previous page

1 lesson
  1. 51
    Replacement and repeated dilution1 practice test

5 lessons
  1. 52
    Work, rate and efficiency
  2. 53
    Combined work and remaining work
  3. 54
    Efficiency ratios and worker equivalence
  4. 55
    Alternate-day and changing-team work
  5. 56
    Work and wages

6 lessons
  1. 57
    Speed, distance, time and unit conversions
  2. 58
    Average speed for unequal times and distances
  3. 59
    Relative speed and meeting or overtaking
  4. 60
    Trains crossing people, platforms and other trains
  5. 61
    Boats and streams
  6. 62
    Races and circular tracks

2 lessons
  1. 63
    Length, area and volume unit conversions
  2. 64
    Measurement accuracy and dimensional checks

5 lessons
  1. 65
    Perimeter and area of squares and rectangles
  2. 66
    Area and perimeter of triangles
  3. 67
    Parallelogram, rhombus and trapezium areas
  4. 68
    Circumference, circle and semicircle areas
  5. 69
    Composite figures, paths and shaded regions

6 lessons
  1. 70
    Surface area and volume of cubes and cuboids
  2. 71
    Surface area and volume of cylinders
  3. 72
    Surface area and volume of right circular cones
  4. 73
    Surface area and volume of spheres and hemispheres
  5. 74
    Right prisms and right pyramids with triangular or square bases
  6. 75
    Composite solids and volume-preserving conversions

7 lessons
  1. 76
    Variables, expressions and algebraic operations
  2. 77
    Standard algebraic identities
  3. 78
    Elementary factorisation
  4. 79
    Linear equations in one variable
  5. 80
    Pairs of linear equations
  6. 81
    Surds and simplification
  7. 82
    Graphs of linear equations

9 lessons
  1. 83
    Lines, angles and parallel-line relationships
  2. 84
    Triangle angle and side properties
  3. 85
    Medians, altitudes, angle bisectors and triangle centres
  4. 86
    Congruence and similarity of triangles
  5. 87
    Pythagoras theorem and elementary applications
  6. 88
    Properties of quadrilaterals
  7. 89
    Interior and exterior angles of polygons
  8. 90
    Circle chords and angle properties
  9. 91
    Tangents and common tangents to circles

6 lessons
  1. 92
    Trigonometric ratios in a right triangle
  2. 93
    Standard-angle values
  3. 94
    Basic trigonometric identities
  4. 95
    Complementary-angle relationships
  5. 96
    Degrees and radians
  6. 97
    Elementary heights and distances

3 lessons
  1. 98
    Perfect squares and elementary square patterns
  2. 99
    Square roots by factorisation and division
  3. 100
    Estimating square roots

50 lessons across 10 modules

Lesson 70 of 100 | Quantitative Aptitude / Solid Mensuration / ठोस क्षेत्रमिति

Surface area and volume of cubes and cuboids

Learning outcome

Calculate surface area and volume of cubes and cuboids, choosing the correct faces and dimensions for a closed solid or an open container.

Concepts and assumptions

Surface area measures boundaries in square units; volume measures space in cubic units. Treat dimensions as exact. Containers have negligible wall thickness, and capacity uses internal dimensions.

For a cuboid, choose a rectangular base l by b and perpendicular height h. Each horizontal layer has area l × b; stacking layers through height h gives V = l × b × h.

Opposite faces form three equal pairs, so total surface area, TSA = 2 × (l × b + b × h + h × l). Lateral surface area, LSA = 2 × h × (l + b), includes four walls but excludes both designated bases.

For a cube with edge a, V = a³, TSA = 6 × a² and LSA = 4 × a².

A top-open cuboidal container has one base and four walls: area = l × b + 2 × h × (l + b). This counts one specified surface of each wall, not both inside and outside. Exposed area counts only uncovered or requested surfaces.

Use 1 L = 1000 cm³. Convert lengths to compatible units before multiplying. No rounding is needed.

Worked examples

Example 1 — Cube. A solid cube has edge 5 cm. Each face has area 5 × 5 = 25 cm². LSA = 4 × 25 = 100 cm²; TSA = 6 × 25 = 150 cm². Volume = 5 × 5 × 5 = 125 cm³.

Example 2 — Cuboid. A solid cuboid is 18 cm long, 11 cm broad and 7 cm high. Face areas are 198, 77 and 126 cm². TSA = 2 × (198 + 77 + 126) = 802 cm². Volume = 18 × 11 × 7 = 1386 cm³.

Example 3 — Open tank. A top-open tank has internal dimensions 60 cm × 35 cm × 40 cm high. Coat only its inner base and four inner walls. Area = 60 × 35 + 2 × 40 × (60 + 35) = 2100 + 7600 = 9700 cm². Brimful capacity = 60 × 35 × 40 = 84000 cm³ = 84 L.

Common mistakes

Do not add a nonexistent top, count unrequested surfaces, or use external dimensions for internal capacity. Area and volume require different units and different conversion factors.

Practice questions

  1. A cube has edge 7 cm. Find its lateral area, total area and volume.
  2. A cuboid measures 16 cm × 9 cm × 5 cm. Find its total area and volume.
  3. A top-open tank has internal length 50 cm, breadth 32 cm and height 25 cm. Find its inner base-and-wall area and capacity.
  4. A cuboid has a 12 cm × 8 cm base and volume 960 cm³. Find its perpendicular height and lateral area.

Worked solutions

  1. LSA = 4 × 7² = 196 cm²; TSA = 6 × 7² = 294 cm². Volume = 7³ = 343 cm³.
  2. TSA = 2 × (144 + 45 + 80) = 538 cm². Volume = 16 × 9 × 5 = 720 cm³.
  3. Area = 50 × 32 + 2 × 25 × (50 + 32) = 1600 + 4100 = 5700 cm². Capacity = 50 × 32 × 25 = 40000 cm³ = 40 L.
  4. Base area = 12 × 8 = 96 cm². Height = 960 ÷ 96 = 10 cm. LSA = 2 × 10 × (12 + 8) = 400 cm².
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