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Exam study plan

SSC CGL Preparation: Concepts and Practice

Free

Build your SSC CGL foundations with English and Hindi lessons, worked examples and explained practice across Quantitative Aptitude, General Intelligence and Reasoning, English Comprehension and General Awareness. Study arithmetic, algebra, geometry and trigonometry; practise analogy, classification, series, directions, ranking and clocks; strengthen grammar and constitutional basics. Use the linked topic tests to check understanding and review mistakes. Coverage is expanding subject by subject and does not yet represent the complete SSC CGL syllabus. See the module list and mock-test section for currently available material.

Lessons

Subject → Module → Lesson

English ComprehensionGeneral AwarenessGeneral Intelligence and ReasoningQuantitative Aptitude
Course outline 100
63 / 100
Lessons 51–100 · Page 2 of 2
Previous page

1 lesson
  1. 51
    Replacement and repeated dilution1 practice test

5 lessons
  1. 52
    Work, rate and efficiency
  2. 53
    Combined work and remaining work
  3. 54
    Efficiency ratios and worker equivalence
  4. 55
    Alternate-day and changing-team work
  5. 56
    Work and wages

6 lessons
  1. 57
    Speed, distance, time and unit conversions
  2. 58
    Average speed for unequal times and distances
  3. 59
    Relative speed and meeting or overtaking
  4. 60
    Trains crossing people, platforms and other trains
  5. 61
    Boats and streams
  6. 62
    Races and circular tracks

2 lessons
  1. 63
    Length, area and volume unit conversions
  2. 64
    Measurement accuracy and dimensional checks

5 lessons
  1. 65
    Perimeter and area of squares and rectangles
  2. 66
    Area and perimeter of triangles
  3. 67
    Parallelogram, rhombus and trapezium areas
  4. 68
    Circumference, circle and semicircle areas
  5. 69
    Composite figures, paths and shaded regions

6 lessons
  1. 70
    Surface area and volume of cubes and cuboids
  2. 71
    Surface area and volume of cylinders
  3. 72
    Surface area and volume of right circular cones
  4. 73
    Surface area and volume of spheres and hemispheres
  5. 74
    Right prisms and right pyramids with triangular or square bases
  6. 75
    Composite solids and volume-preserving conversions

7 lessons
  1. 76
    Variables, expressions and algebraic operations
  2. 77
    Standard algebraic identities
  3. 78
    Elementary factorisation
  4. 79
    Linear equations in one variable
  5. 80
    Pairs of linear equations
  6. 81
    Surds and simplification
  7. 82
    Graphs of linear equations

9 lessons
  1. 83
    Lines, angles and parallel-line relationships
  2. 84
    Triangle angle and side properties
  3. 85
    Medians, altitudes, angle bisectors and triangle centres
  4. 86
    Congruence and similarity of triangles
  5. 87
    Pythagoras theorem and elementary applications
  6. 88
    Properties of quadrilaterals
  7. 89
    Interior and exterior angles of polygons
  8. 90
    Circle chords and angle properties
  9. 91
    Tangents and common tangents to circles

6 lessons
  1. 92
    Trigonometric ratios in a right triangle
  2. 93
    Standard-angle values
  3. 94
    Basic trigonometric identities
  4. 95
    Complementary-angle relationships
  5. 96
    Degrees and radians
  6. 97
    Elementary heights and distances

3 lessons
  1. 98
    Perfect squares and elementary square patterns
  2. 99
    Square roots by factorisation and division
  3. 100
    Estimating square roots

50 lessons across 10 modules

Lesson 63 of 100 | Quantitative Aptitude / Measurement / मापन

Length, area and volume unit conversions

Learning outcome

Convert length, area, volume and capacity units correctly, including calculations whose measurements initially use different units.

Concepts and assumptions

Length measures distance, area measures surface coverage, and volume measures occupied three-dimensional space. Their units must therefore scale differently.

Since 1 m = 100 cm, a square measuring 1 m on each side contains 100 × 100 = 10,000 squares of area 1 cm². Thus 1 m² = 10,000 cm², not 100 cm².

A cube with side 1 m contains 100 × 100 × 100 = 1,000,000 cubes of volume 1 cm³. Thus 1 m³ = 1,000,000 cm³.

Generally, if one larger length unit equals k smaller units, multiply by k for length, k² for area and k³ for volume. Reverse conversions require division. Identify the quantity before choosing the factor.

Useful exact identities are: 1 km = 1,000 m; 1 cm = 10 mm; 1 hectare = 10,000 m²; 1 L = 1,000 cm³; 1 mL = 1 cm³. Consequently, 1 m³ = 1,000 L. Capacity describes the usable internal volume of a container; litres do not measure mass.

Use one consistent unit before adding lengths or calculating areas and volumes. Conversion identities are exact, but converting a measured value does not improve its accuracy. Treat the exercise dimensions as ideal values; all answers here require no rounding.

Worked examples

Example 1 — Adding lengths. A route contains a 2.35 km section followed by a 480 m section. Find its total length in metres and kilometres.

First section = 2.35 × 1,000 = 2,350 m. Total = 2,350 + 480 = 2,830 m. Converting back: 2,830 ÷ 1,000 = 2.83 km.

Example 2 — Converting area. A rectangular mat is 1.8 m long and 75 cm wide. Find its area in m² and cm².

Width = 75/100 = 0.75 m. Area = 1.8 × 0.75 = 1.35 m². Area in cm² = 1.35 × 10,000 = 13,500 cm². Check using centimetres: length = 180 cm; 180 × 75 = 13,500 cm².

Example 3 — Container capacity. A rectangular tank has internal dimensions 80 cm × 50 cm × 45 cm. Find its full capacity in litres and m³.

Internal volume = 80 × 50 × 45 = 180,000 cm³. Capacity = 180,000/1,000 = 180 L. Volume = 180,000/1,000,000 = 0.18 m³. These are internal dimensions, so wall thickness is not subtracted.

Common mistakes

Applying a length factor to an area or volume; multiplying unlike length units without conversion; confusing m² with m³; treating litres as kilograms without density information.

Practice questions

  1. Express 0.72 km + 850 cm in metres.
  2. Convert 3.6 m² to cm² and 85,000 mm² to cm².
  3. Convert 0.045 m³ to litres and cm³.
  4. A 0.84-hectare plot is divided entirely into equal 350 m² plots, with no land reserved for paths. How many plots result?

Worked solutions

  1. 0.72 km = 720 m; 850 cm = 8.5 m. Total = 720 + 8.5 = 728.5 m.
  2. 3.6 × 10,000 = 36,000 cm². Since 1 cm² = 100 mm², 85,000/100 = 850 cm².
  3. Litres = 0.045 × 1,000 = 45 L. Cubic centimetres = 0.045 × 1,000,000 = 45,000 cm³.
  4. Total area = 0.84 × 10,000 = 8,400 m². Number of plots = 8,400/350 = 24; the units cancel because one area is divided by another.
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