Skip to content

Syllabus · Quantitative Aptitude

All topics in this subject
Number System8
Arithmetic Operations4
Squares and Square Roots3
Decimals3
Fractions4
Ratio and Proportion5
Percentages7
Averages3
Commercial Arithmetic5
Simple Interest3
Compound Interest4
Partnership2
Mixtures3
Work and Time5
Speed, Distance and Time6
Algebra7
Geometry9
Measurement2
Plane Mensuration5
Solid Mensuration6
Trigonometry6

Tangents and common tangents to circles

Lesson 91 of 1003 minFree

Learning outcome

Calculate tangent lengths and angles, distinguishing direct and transverse common tangents.

Concepts and assumptions

A tangent meets a circle at exactly one point and is perpendicular to the radius there. Conversely, a perpendicular to a radius at its circle endpoint is tangent.

For P outside a circle of centre O and radius r, tangents PA and PB touch at A and B. Right triangles OAP and OBP share hypotenuse OP and have equal radii, so:

PA = PB = √(OP² − r²).

Guaranteed equality uses the same external point and circle. Also, ∠APB + minor ∠AOB = 180°.

If ray AT is tangent at A, AB is a chord, and circle point C is opposite T across line AB, the tangent–chord theorem gives ∠TAB = ∠ACB.

For common tangents, take radii R ≥ r > 0 and centre distance d > R + r: circles neither touch nor overlap. Four common tangent lines exist; lengths below mean contact-to-contact segments:

Direct: Both centres lie on the same side of the tangent line. Length = √(d² − (R − r)²).

Transverse: Centres lie on opposite sides; the contact segment crosses the segment joining the centres. Length = √(d² − (R + r)²).

Pythagoras uses hypotenuse d and perpendicular offsets R − r or R + r. Other configurations need separate existence checks.

Worked examples

Example 1 — Two tangent segments. From P, tangents PA and PB touch a circle of centre O and radius 7 cm; OP = 25 cm. Triangle OAP is right-angled at A: PA² = 25² − 7² = 576. Thus PA = PB = 24 cm.

Example 2 — Angle between tangents. From P, tangents PA and PB touch a circle of centre O at A and B, with ∠APB = 64°. Quadrilateral OAPB has right angles at A and B. Thus minor ∠AOB = 360° − 90° − 90° − 64° = 116°.

Example 3 — Direct versus transverse. Two circles have radii 17 cm and 7 cm, with centres 26 cm apart. Since 26 > 17 + 7 = 24, both types exist. Direct length = √(26² − 10²) = √576 = 24 cm. Transverse length = √(26² − 24²) = √100 = 10 cm.

Common mistakes

Use the contact radius for perpendicularity. Do not assume equality across different points or circles. Direct formulas use the radii’s difference; transverse formulas use their sum. Always check separation.

Practice questions

  1. P is external to a circle with centre O, radius 9 cm and OP = 15 cm. Find its tangent length.
  2. Ray AT is tangent at A; AB is a chord. Point C lies on the circle opposite T across line AB. If ∠TAB = 38°, find ∠ACB.
  3. Two externally separated circles have radii 18 cm and 3 cm, with centres 25 cm apart. Find the direct common-tangent length.
  4. Two externally separated circles have radii 9 cm and 6 cm, with centres 17 cm apart. Find the transverse common-tangent length.

Worked solutions

  1. The contact radius and tangent form a right angle. Tangent² = 15² − 9² = 144, so the length is 12 cm.
  2. C is in the required opposite segment. The tangent–chord theorem gives ∠ACB = ∠TAB = 38°.
  3. Since 25 > 18 + 3 = 21, separation holds. Direct length = √(25² − (18 − 3)²) = √(625 − 225) = 20 cm.
  4. Since 17 > 9 + 6 = 15, transverse tangents exist. Length = √(17² − (9 + 6)²) = √(289 − 225) = 8 cm.

Sign in to keep your progress. Sign in