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Syllabus · Quantitative Aptitude

All topics in this subject
Number System8
Arithmetic Operations4
Squares and Square Roots3
Decimals3
Fractions4
Ratio and Proportion5
Percentages7
Averages3
Commercial Arithmetic5
Simple Interest3
Compound Interest4
Partnership2
Mixtures3
Work and Time5
Speed, Distance and Time6
Algebra7
Geometry9
Measurement2
Plane Mensuration5
Solid Mensuration6
Trigonometry6

Compound ratios and changing ratios

Lesson 24 of 1003 minFree

Learning outcome

Form compound ratios, connect shared quantities, and solve changing-ratio problems by tracking changes precisely.

Understanding compound and changing ratios

The compound ratio of a:b and c:d is (a × c):(b × d). This follows from multiplying the fractions a/b and c/d. Multiply corresponding terms, not crosswise; cross-products serve comparison or proportion testing.

If A:B and B:C are known, multiplying A/B by B/C cancels the shared B and gives A/C. This gives the endpoint ratio, not the full three-term ratio. For A:B:C, scale until the B terms match.

Write initial amounts as au and bu, where u > 0 is their common scale and au means a × u. Apply additions or removals to the specified quantities before forming the new ratio. Match units first.

Equal positive scaling preserves a ratio. Equal additions generally change it because relative increases differ; equal initial amounts are an exception. A transfer subtracts from one quantity and adds to the other, preserving the total. Remaining quantities must stay positive.

Worked example 1

Positive lengths satisfy A:B = 2:3 and B:C = 4:5. Find A:C and A:B:C.

Compounding gives A:C = (2 × 4):(3 × 5) = 8:15. For A:B:C, multiply 2:3 by 4 to get 8:12, and 4:5 by 3 to get 12:15. Matching B now gives A:B:C = 8:12:15.

Worked example 2

Two containers hold water in ratio 3:5. Add 8 L to the first only; the second stays unchanged. The new ratio is 5:7. Find the initial amounts.

Let initial amounts be 3u L and 5u L. Then (3u + 8)/(5u) = 5/7. Cross-multiplication gives 21u + 56 = 25u, so 56 = 4u and u = 14. Initially there were 42 L and 70 L. After addition, 50:70 simplifies to 5:7.

Worked example 3

Two boxes have beads in ratio 7:5. Transfer 10 beads from the first to the second; nothing else changes. The new ratio is 4:5. Find the initial counts.

Initially, take 7u and 5u. Then (7u − 10)/(5u + 10) = 4/5. Thus 35u − 50 = 20u + 40, giving 15u = 90 and u = 6. Initially there were 42 and 30 beads. Afterwards there are 32 and 40, giving 4:5. Both totals are 72.

Common mistakes

Identify what a compound ratio represents. Equal additions are not equal scaling. Transfers change both quantities; check that remaining amounts are positive.

Practice questions

  1. Find the compound ratio of 3:8 and 4:9.
  2. For positive quantities, P:Q = 3:4 and Q:R = 6:7. Find P:Q:R and P:R.
  3. Two containers hold water in ratio 2:3. Adding 6 L to each changes it to 3:4. Find the initial amounts.
  4. Two containers hold water in ratio 5:8. Remove 9 L from only the second; the first stays unchanged. The new ratio is 5:6. Find initial amounts.

Worked answers

  1. Multiply corresponding terms: (3 × 4):(8 × 9) = 12:72 = 1:6.
  2. Scale the ratios to 9:12 and 12:14. Hence P:Q:R = 9:12:14 and P:R = 9:14.
  3. Write (2u + 6)/(3u + 6) = 3/4. Then 8u + 24 = 9u + 18, so u = 6. Initially: 12 L and 18 L. Afterwards: 18 L and 24 L, giving 3:4.
  4. Write (5u)/(8u − 9) = 5/6. Then 30u = 40u − 45, so u = 4.5. Initially: 22.5 L and 36 L. Afterwards: 22.5 L and 27 L, both positive, giving 5:6.

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